A company has two plants for manufacturing scooters .Plant 1 manufactures 70% of the scooter and plant 2 manufactures 30% of the scooters .At plant 1 ,30% of the scooters are maintaing pollution norms and atcplant 2 ,90% of the scooters are mainting pollution norms.A scooter is choosen at random and is found tobe fit on pollution norms. Find the probability that it has come from plant 2.
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Answer:
This question can be solved using Bayes's Theorem
i.e P(E1/A) ={ P(A/E1)*P(E1)}/P(A/E1)*P(E1) + P(A/E2)*P(E2)
Step-by-step explanation: For this question
let the probability of selection of plant 1 be P(E1) = 70/100
And plant 2 be P(E2)= 30/100
Let A: event of selection of one scooter maintaining pollution norms
Then acc to question
P(A/E1)= 30/100
P(A/E2)=90/100
We have to find P(E2/A)
Using Bayes's Theorem
P(A/E2)= {90/100*30/100}/ 90/100*30/100 + 70/100*30/100
= 27/48 = 7/16
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