A meeting hall has 20 seats in the first row 24 seat inthe second row 28 seat in the third row and so o and has in all 30 rows how any seats are there in the meeting hall
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First row has 20 seats..
Second row has 24 seats..
Third row has 28 seats..
There are total of 30 rows.
So, let a = 20
d = (24-20) = 4
n = 30
Therefore, total seats are given by, n/2{2a+(n-1)d}
15{40+(30-1)4}
15{40+(29)4}
15(40+116)
15(156)
==】So, total number of seats in the hall are 2,340.
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Hope it helps.
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