A company makes a mixture which contains 2% alcohol. If 10 litres of alcohol is added to the mixture, then the concentration increases to 5%. What is the approx. Quantity of the mixture?
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The options for this question are missing: here are the missing options:
A. 316
B. 315
C. 310
D. 300
Answer:
A. 316
Let in the mixture of x liters, quantity of alcohol=(2/100)*x=x/50 liters.
When 10 liters of alcohol is added, quantity of mixture= (x+10) liters and
Quantity of alcohol=10+ x/50 liters.
So % of alcohol in new mixture= (10 + x/50)/(x+10) = 5/100
=>100(500+x) = 250(x+10)
=> 2(500+x) =5(x+10)
=> x= 950/3= 316.66 ~ 316 liters.
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