Question

A company sells boxes of cow bells (b) for $20 and boxes of air horns (h) for $30. They can make a batch of cow bells that fills 8 boxes or a batch of air horns that fills 9 boxes. The company only has 53 boxes. Which system of equations helps the company plan to make $275?

Answer 1

Answer:

$8b+9h = 53$ and $20b + 30h =275$

Step-by-step explanation:

Given : A company sells boxes of cow bells (b) for $20 and boxes of air horns (h) for $30. They can make a batch of cow bells that fills 8 boxes or a batch of air horns that fills 9 boxes. The company only has 53 boxes.

To find : Which system of equations helps the company plan to make $275?

Solution :

Let, b be the boxes of cow bells and

h be the boxes of air horns

Total number of boxes = 53

They can make a batch of cow bells that fills 8 boxes or a batch of air horns that fills 9 boxes.

The equation is $8b+9h = 53$

The cost of boxes company plan to make = $275

A company sells boxes of cow bells (b) for $20 and boxes of air horns (h) for $30.

The equation is $20b + 30h =275$

Therefore, The two system of equation form with the given statements are

$8b+9h = 53$ and $20b + 30h =275$