Question

A complete 7/10 work in 15 days then he complete the remaining work with the help of B in 4 days time required for A and B together to complete the entire work is :

1 . 32/3
2. 38/ 3
3. 40/3
4. 33/4
5. none of these

Answer 1

$\frac{7}{10}$ part of work has been completed by A in 15 days.

Then,
Rest work $= 1- \frac{7}{10} = \frac{3}{10}$ part.

Given That $\frac{3}{10}$ part of the work is completed by A and B together in 4 days.

So,
(A+B) completed the $\frac{3}{10}$ of work in 4 days.

⇒ (A+B)'s 1 day's work $= \frac{3}{10*4} = \frac{3}{40}$

∴ (A+B) can complete the work in $\frac{40}{3}$ $= 13 \frac{1}{3}$ days.

Hope This Helps :)

Answer 2

Answer:

40/3

Step-by-step explanation:

A+B ‘s work in 4 days

=1–work done by A in 15days

=1–7/10

=3/10

A+B ‘s work for one day=3/40

So, Number of days required by A+B to complete the said work = 40/3 days

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