A complete a work in 10 days, B can destruct the same work in 15 days. If they work on alternate day then work will finish in how many days?
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Step-by-step explanation:
A=2 days
B=-3 days (minus show=destroy)
How many days work complete=?
So let’S take L.C.M of 3 and 2. That is 6
{mean work = 6 unit}
A=6/2 =3 unit per day
B=6/-3=-2 unit per day
Condition- if they work on alternative days (staring with A)
First day A do 3 unit and next (second) day B destroy 2 unit
According to condition-
A+B+A+B+A…
(3–2)+(3–2)+(3–2)+3=1+1+1+3=6unit in 7 days
A work 4days and B work 3 days
So total days =7 days
So finally work will be complete 7 days
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