Question

A completes a work in 24 days. If B is 60% more efficient than A, the how many days does B take to complete twice the work?​

Answer 1

Step-by-step explanation:

since B is 60% efficient than A, thus he takes less time than A

B=60%A

B=60×24/100

B=14.4 days

$\frac{1}{b} + \frac{1}{a} = \frac{1}{t} \\ \frac{1}{14.4} + \frac{1}{24 } = \frac{1}{t} \\ \frac{10}{144} + \frac{6}{144} = \frac{1}{t} \\ \frac{16}{144} = \frac{1}{t} \\ \\ thus \\ \frac{1}{9} = \frac{1}{t} \\ t = 9days$

hence together they will take 9 days