Question

A compound (60g) on analysis gave 24g of C,
4g of H and 32g of 0. Its empirical formula is :
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Answer 1

Answer:

C moles =24/12 =2

H moles =4/1 =4

O moles =32/16 =2

Ratio of moles C :H: O

2 :4 :2

Simplest ratio C1H2O1

Empirical formula = C H2 O

Answer 2

Answer:

Empirical Formula is the simplest ratio of the no.of atoms present in a molecule.

Given 24g of C = 2 moles

4g of H = 4 moles

32g of O = 2 moles

Their ratio is 2:4:2 i.e. 1:2:1

So, Empirical Formula is CH2O.

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