Question

A compound (80 g) on analysis gave C = 24 g, H=4 g, O
= 32 g. Its empirical formula is​

Answer 1

Answer:

Explanation:

for C no of moles=24/12=2

     H no of moles=4/1=4

     O no of moles=32/16=2

since 2 is the smallest value divide by 2

C=2/2=1

H=4/2=2

O=2/2=1

empirical formula=CH₂O

MOLECULAR formula=C₂H₄O₂