Question

A compound A(C4H8)on treatment with HBr gives compound B which is optically inactive.Which is the IUPAC name of A?​

Answer 1

Answer:

2-bromobutane is the IUPAC name

Answer 2

Answer:

• Compound A $\left(\mathrm{C}_{4} \mathrm{H}_{8}\right)$ is 1-butene which reacts with HBr to give 1-bromobutane under the presence of hydrogen peroxide.
• A compound becomes optically inactive if it becomes incapable of optical rotation and the compound becomes achiral.
• The racemic mixture of 1-bromobutane becomes an optically inactive product even though the chiral centre formation is present.
• The alkyl bromide 1-bromobutane has carbon attached with four different groups, it turns achiral and hence becomes optically inactive. Mirror images cannot be superimposed under these conditions.