Question

A compound A molecular formula C2H4O2 reacts with sodium metal to form a compound B and envoles a gas which burns with a pop sound

Answer 1

Compound A is CH3COOH
Compound B is CH3COONa
Chemical reaction in sequence are as follows:
CH3COOH + Na →CH3COONa + H2
CH3OH + CH3COOH+ acid ⇒ CH3COOCH3+ H2O
CH3COOH + NaOH → CH3COONa + H2O
CH3COOCH3 + NaOH → CH3COONa + CH3OH
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Answer 2

Answer:

2 CH₃COOH + 2 Na ⇒  2 CH₃COONa + H₂O

      ( A )                                   ( B )

CH₃COOH + C₂H₅OH ⇒  CH₃COOC₂H₅ + H₂O

                        ( C )                 ( D )

CH₃COOC₂H₅ + NaOH  ⇒ C₂H₅OH + CH₃COONa

Therefore we identified

A - CH₃COOH

B - CH₃COONa

C - C₂H₅OH

D - CH₃COOC₂H₅