Question

A room is 5m 40cm long and 4m 50cm broad.its area is

Answer 1

$\underline{\textsf{Given:}}$

$\textsf{Length of the room is 5m 40cm}$

$\textsf{Breadth of the room is 4m 50cm}$

$\underline{\textsf{To find:}}$

$\textsf{Area of the room}$

$\underline{\textsf{Solution:}}$

$\textsf{We know that,}$

$\boxed{\mathsf{1\;metre=100\;centimetre}}$

$\textsf{Length of the room = 5m 40cm=540\,cm=5.4\,m}$

$\textsf{Breadth of the room = 4m 50cm=450\,cm=4.5\,m}$

$\textsf{Now,}$

$\mathsf{Area\;of\;the\;room}$

$\mathsf{=Length{\times}Breadth}$

$\mathsf{=5.4{\times}4.5}$

$\mathsf{=24.3\,m^2}$

$\underline{\textsf{Answer:}}$

$\mathsf{Area\;of\;the\;room\;is\;24.3\;m^2}$

$\underline{\textsf{Find more:}}$

The area of a rectangle is 120m^2. If its length is decreased by 8m and its width is increased by 4m, the area stays the same. Find the perimeter of the original rectangle if all measurements are whole numbers, and show your working. Please answer, much appreciated.

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Ponit T is in the interior of rectangle pqrs prove that TQ square + TS square is equal to TP square + TR square as shown in the figure draw AB parallel to SR

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Answer 2

Step-by-step explanation:

length of the room=5m 40cm=5.4m

breadth of the room=4mb50cm=4.5m

Area of the room=l×b

=5.4×4.5

=24.3 sq m

Hence,Area of the room is 24.3 sq m