A compound c (molecular formula c2h4o2) reacts with na-metal to form a compound r and evolves a gas which burns with a pop sound. compound c on treatment with an alcohol A in presence of an acid forms a sweet smelling compound S(molecular formula c3h5o2), on addition of NaOH to C, it also gives R and water, S on treatment with NaOH solution gives back R and .A identify C, R, A, S and write down the reaction involved
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c is ethanoic acid
r is CH3COONa
A is ethanol
S is ester CH3COOC2H5
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Answer:
2 CH₃COOH + 2 Na ⇒ 2 CH₃COONa + H₂ ↑
( A ) ( B )
CH₃COOH + C₂H₅OH ⇒ CH₃COOC₂H₅ + H₂O
( C ) ( D )
CH₃COOC₂H₅ + NaOH ⇒ C₂H₅OH + CH₃COONa
Therefore we identified
A - CH₃COOH
B - CH₃COONa
C - C₂H₅OH
D - CH₃COOC₂H₅
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