Question

A compound contain c=41.4% ,h=5.75%,N=16.08% ,and rest oxygen.Find the empirical formula of the following.

Answer 1

empirical formula- C3H5NO2 12×3+1×5+14+2×16--- 87 molecular mass - n × vd - 86.6

n - molecular mass

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emipirical formula

n= 0.99 ~ 1

molecular formula = n× E.F

= C3H5NO2

Answer 2

Answer:

C3H4NO4

Explanation :

Refer the attachment given below.

Hope this answer helps you.