Question

a compound contains 28% of Nitrogen and 72% of a metal by weight three atom of the metal combined with two atom of Nitrogen find the atomic weight of the metal ​

Answer 1

Answer:

According to problem, three atoms of M combine with 2 atoms of N

Equivalent wt of N = 14/3 (∵ valency of N in compound is 3)

∵ 288 g n combines with = 72g metal

∴ 14/3 N combines with = 72/28 * 14/3 = 12

∴ Eq. wt. of metal = 12

At wt of metal = Eq. wt * valency = 12 * 2 = 24 [Valency]

Answer 2

Explanation:

CHEMISTRY

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Asked on November 22, 2019 by

Suneetha Jeet

A compound contains 28 percent of nitrogen and 72 percent of a metal by weight. Three atoms of the metal combine with two atoms of N. Find the atomic weight of the metal.

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ANSWER

28 g of nitrogen combines with 72 g of metal. Three atoms of metal combine with two atoms of nitrogen. This means the valency of metal is 2.

Let M be the atomic mass of metal.

Equivalents of N=

3

14

28

=

6

1

Equivalents of metal =

2

M

72

=

M

144

6

1

=

M

144

⇒M=

6

144

=24 g

Hence, the atomic weight of metal is 24 g.