Question

A compound contains 32% Karbonn 4% hydrogen and rate oxygen its vapour density is 75 calculate the empirical and molecular formula ​

Answer 1

Answer:

Explanation:

molecular mass = 2×VD

= 2×75

= 150.

now carbon is 32%

=> mass of carbon in the compound = 32%

mass of carbon = 32/100 ×150

= 48gm

= 4 mole ofC atoms

mass of 4% of Hydrogen = 4/100 × 150

= 6gm

= 6 moles of H atoms

mass of rest 64 % of oxygen = 64/100 × 150

= 96gm

= 6 moles of O atoms

so we have 4 carbon, 6 Hydrogen and 6 oxygen.

so we can take 2 common out of them.

empirical formula C2 H3 O3.

Answer 2

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