A compound contains 40% carbon 6.67% hydrogen is 33.33% oxygen review the molecular formula of the compound is the molar mass is 180 g m o l
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we work of 100 g of compound and calculate the number of moles of each element
moles of C = 40 / 12 = 3.33 moles
moles of H = 6.67 /1 = 6.67
moles of O = 53.33 / 16 = 3.33 moles
molar ratio of C : H : O = 3.33 : 6.67 : 3.33
= 1 : 2 : 1
empirical formula is CH2O
Anonymous:
hey user ...in which grade u are ??
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Answer:
we have given the percentage
so,
mole of C = 40/12= 3.33
". ". H = 6.67/1 = 6.67
". ". O = 53.33/16 = 3.33
molecular formula = 1 : 2 : 3
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