if the bandwidth of a signal is 5 khz and the lowest frequency is 52 khz what is the highest frequency?
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f₂ = highest frequency = ?
f₁ = lowest frequency = 52 kHz
Δf = bandwidth = 5 kHz
Bandwidth is given as
Δf = f₂ - f₁
5 = f₂ - 52
f₂ = 57 kHz
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Concept:
The bandwidth of a signal is the difference between the maximum and minimum frequency of a certain continuous frequency band. The Bandwidth can be calculated as:
Bandwidth(B)= Highest Frequency(fH) - Lowest Frequency (fL)
Given:
fL= 52KHz
B= 5KHz
Find: fH
Solution:
∵ B= fH - fL
⇒ fH = B + fL
putting the values gives:
fH = 5 KHz +52 KHz
fH= 57KHz
Hence the value of the highest frequency is 57 KHz
#SPJ2
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