a compound crystallizes in bcc structure. what is unit cell edge length of daimeter of its atom is 120 pm?
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ans is 150primemeradian
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51.8
The expression for the density of the unit cell is given below:
d=a3×NAn×M
Given that,
a=288 pm =288×10−10 cm
d=7.2 g cm−3
n=2
Substituting values in the above expression, we get
7.2=(288×10−10)3×6.023×10232×M
⟹M=27.2×(288×10−10)3×6.023×1023=51.8
Hence, the atomic mass of the element is 51.8 g/mol.
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