Question

A compound having 22.4L volume completely reacts with 112L oxygen at NTP. Compound is...
i)C3H4
ii)C3H8
iii)C3H3
iv)Both (i) and (iii)​

Answer 1

Hey Dear,

◆ Answer -

(ii) C3H8

◆ Explanation -

Moles of supposed compound are -

n(X) = 22.4 / 22.4 = 1 mol

Moles of oxygen are -

n(O2) = 112 / 22.4 = 5 mol

So in combustion reaction, 1 mol of compound reacts with 5 mol of O2.

Only compound that balances such reaction is C3H8. So now reaction will be -

C3H8 + 5 O2 --> 3 CO2 + 4 H2O

Hope this helps you...