Question

A compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3rd of tetrahedral voids.

Answer 1

The ccp lattice is formed by the atoms of the element N.

Here, the number of tetrahedral voids generated is equal to twice the number of atoms of the element N.

According to the question, the atoms of element M occupy 1/3rd of the tetrahedral voids.

Therefore, the number of atoms of M is equal to 2×1/3=2/3rd of the number

of atoms of N.

Therefore, ratio of the number of atoms of M to that of N is M: N
=2/3:1

=2:3

Thus, the formula of the compound is M2 N3.

Answer 2

${\huge{\underline{\bold{\orange{Question-}}}}}$

A compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3rd of tetrahedral voids. What is the formula of the compound?

${\huge{\underline{\bold{\green{Answer-}}}}}$

Let the number of atoms of the element N = n

Number of tetravalent voids = 2n

It is given that the atoms of element M occupy 1/3 of the tetrahedral voids.

So that the number of atoms of M = (1/3) × 2n

Ratio of the number of atoms of M and N

M:N =2n/3:n

Multiplying the 3 and divide by n we get

M:N = 2:3

Hence, the formula of the compound is M2N3 .

===================================