Question

If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons would flow through the wire?

Answer 1

I = 0.5 A

t = 2 hours = 2 × 60 × 60 s = 7200 s

Thus, Q = It

= 0.5 A × 7200 s

= 3600 C

We know that 96487C = 6.023 X 1023 number of electrons.

Then,

3600 C= 6.023×10^23×3600/96487

=2.25×10^22

Hence, 2.25 X 10^22number of electrons will flow through the wire.

Answer 2

Hey !!

Q ( coulomb ) = I ( ampere ) × t (s) = ( 0.5 ampere ) ( 2 × 60 × 60 s)

                           = 3600 C

A flow of 96500 C is equivalent to the flow of 1 mole of electrons, 6.02 × 10²³ electrons

 ∴ 3600 C is equivalent to flow of electrons = 6.02 × 10²³ / 96500 × 3600

           = 2.246 × 10²² electrons.

Hope it helps you !!