Chemistry, asked by pra7av, 10 months ago

A compound is found to contain 63.52 % iron and 36.48% sulfur. Find its empirical formula.​

Answers

Answered by Manveerpbx1
27

Answer:The answer is FeS

Explanation:

Make 6 columns element percentage composition atomic mass relative no. of moles simple ratio and simplest whole no. ratio

Relative no. of moles= percentage composition divided by it's atomic mass.

Hope you get the best from this attached file.

Attachments:
Answered by qwmagpies
7

Given: A compound is found to contain 63.52 % iron and 36.48% sulfur.

To find: We have to find its empirical formula.

Solution:

The atomic weight of iron or Fe is 56 and the atomic weight of Sulfur is 32.

A compound is found to contain 63.52 % iron and 36.48% sulfur.

Thus the relative number of moles of Fe is 63.52/56=1.1.

The relative number of moles of S is 36.48/32=1.1.

The ratio between the number of iron to sulfur is 1.1:1.1

=1:1

Thus, the empirical formula of the compound is FeS.

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