Question

a man starts at a corner along the side of a square field of length l and reaches the opposite corner in time t prove that his average velocity is l✓2/t​

Answer 1

Answer:

Man starts from a corner and reaches to the opposite corner.

Velocity deals with magnitude as well as direction.

So, here, if he reaches to the opposite corner, it means, he covers a displacement equal to the diagonal of square.

By using Pythagoras theorem -

→ diagonal^2 = side^2 + side^2

→ diagonal^2 = 2l²

→ diagonal = l√2

Given he takes time = t

→ velocity = displacement / time

→ velocity = l√2 / t

Hence proved