Question

A compound is made up of two elements X and Y in the ratio 2:3 by mass. How many atoms of each of these elements would be present in the molecules of the compound? Give the molecular formula of the compound. ( atomic mass of X=32u, Y=16u)
please give the answer properly and as soon as possible ​

Answer 1

Explanation:

Emp. formula =X

2

Y, At. wt. of X=10, At. wt. of Y=5

∴ Empirical formula mass =2×10+5=25

If Vapour density V.D.=25

Mol. Mass =V.D.×2=25×2=50u

n=

Emp.formula mass

Mol.Mass

=

25

50

=2

Mol. formula =Emp.formula×2=X

2

Y×2

=X

4

Y

2

.

Answer 2

Answer:

Pls mark it as the brainliest answer

Explanation:

How many atoms of each of these elements would be present in the molecules of the compound?

Ans. We have the elements X and Y in the ratio of 2:3

        therefore, X= 2 atoms and Y=3 atoms in one molecule

Give the molecular formula of the compound. ( atomic mass of X=32u, Y=16u)

Ans. We know that X = 2 atoms and Y = 3 atoms

        also, atomic mass of X and Y is 32u and 16u respectively

        So, 2 x Atomic mass of X + 3 x Atomic mass of Y

            =  2 x 32 + 3 x 16

            = 64u  + 48u

            = 112u