A compound made of two elements A and B are found to contain 25% A (Atomic mass 12.5) and 75% B (Atomic mass 37.5). The simplest formula of the compound is _______.
(A) AB
(B) AB₂
(C) AB₃
(D) A₃B
Answers
Answered by
0
heya answer is here......
◇option "C"is correct.
hope it helps u dear
◇option "C"is correct.
hope it helps u dear
Answered by
7
Hello there,
● Answer -
(A) AB
● Explanation -
Lets consider Ma & Mb be molecular weights of element A & B and Wa & Wb be their participating weights in compound.
# Given that -
Wa/Wb = 25/75
Ma = 12.5
Mb = 37.5
# Solution -
Ratio of no of moles participating in compound is -
na/nb = (Wa/Ma) / (Wb/Mb)
na/nb = (Wa/Wb) × (Mb/Ma)
na/nb = (25/75) × (37.5/12.5)
na/nb = 1
Therefore, simplest formula of given compound would be AB.
Hope this helped you...
● Answer -
(A) AB
● Explanation -
Lets consider Ma & Mb be molecular weights of element A & B and Wa & Wb be their participating weights in compound.
# Given that -
Wa/Wb = 25/75
Ma = 12.5
Mb = 37.5
# Solution -
Ratio of no of moles participating in compound is -
na/nb = (Wa/Ma) / (Wb/Mb)
na/nb = (Wa/Wb) × (Mb/Ma)
na/nb = (25/75) × (37.5/12.5)
na/nb = 1
Therefore, simplest formula of given compound would be AB.
Hope this helped you...
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