Question

Energy required for ionisation of 0.02 gm atom of magnesium is xKJ . The amount of energy required to ionize 1 atom of magnesium is

Answer 1

Answer : Energy required to ionize 1 atom of magnesium is 2.02X * 10⁻²¹ kJ

Explanation :

Step 1 : Convert 0.02 g of Mg to mole.

$Mole = \frac{g}{Atomic Mass }$

Atomic mass of Mg is 24.3 g/mol

$mol = \frac{0.02g}{24.3g/mol}$

Moles of Mg are 0.000823

Step 2 : Convert mol to number of atoms

We will use Avogadro's value to find number of atoms in 0.00823 mol Mg

According to Avogadro's law, 1 mol of any substance contains 6.02 x 10²³ particles.

$0.000823mol Mg \times \frac{6.02 \times 10^{23}}{1 mol} =4.95 \times 10^{20} atoms$

Step 3 : Find kJ required for 1 atom

We have been given that the energy required for 4.95 x 10²⁰ atoms is "X" kJ.

Therefore, for 1 atom,  the amount of energy is $\frac{X kJ}{4.95 \times 10^{20}} = 2.02X \times 10^{-21} kJ$

Energy required to ionize 1 atom of magnesium is 2.02X * 10⁻²¹ kJ

Answer 2

Answer:

Answer :Energy required to ionize 1 atom of magnesium is 2.02X * 10⁻²¹ kJ

Explanation :

Step 1 : Convert 0.02 g of Mg to mole.

Atomic mass of Mg is 24.3 g/mol

Moles of Mg are 0.000823

Step 2 : Convert mol to number of atoms

We will use Avogadro's value to find number of atoms in 0.00823 mol Mg

According to Avogadro's law, 1 mol of any substance contains 6.02 x 10²³ particles.

Step 3 : Find kJ required for 1 atom

We have been given that the energy required for 4.95 x 10²⁰ atoms is "X" kJ.

Therefore, for 1 atom,  the amount of energy is

Energy required to ionize 1 atom of magnesium is 2.02X * 10⁻²¹ kJ

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Explanation: