Question

A compound microscope has an eye piece of focal length 10 cm and an objective of focal length 4 cm.

Answer 1

Answer:

Explanation:

Hey there,

If here, you want to find the magnification for the object which is placed at 5 cm from the objective for the given compound microscope then the solution is given below:

It is given that, μo = -5 cm,

fo = -4 cm and fe = 10cm

1/vo = 1/4 + 1/-5 = 1/4 - 1/5 = 1/20

Therefore, vo = 20 cm

Now,  the magnification for the object is:  

M =  Vo / | uo | ( 1 + D/fe)

    = 20/5 (1 + 20/10)

    = 20/5 (10+20/10)

    = 20/5 (3)

    = 60/5

    = 12

Hope this helps..  

Answer 2

Answer:

Here it is common formula to find out the me=−di′do to find out the eye length so the student have to go with the best ideas to move forward and get right answer for all your solution.

We aim to provide best solution and effort for the customer to move forward and get solution. Hope the it give hand for the customer to get a best idea of it.

Explanation: