a compound of 100 litre contains acid and water in the ratio 3 :2. How much acid to be added to get the ratio 3:l?
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75 litre acid should be added
gopika30:
this is not my question
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The acid-to-water ratio of the compound is 3:2, so:
- 3x + 2x = 100
- 5x = 100
- x = 20
Now that we have solved for x, lets find the amount of acid and water in the compound:
- 3 (20) = 60 liters of acid
- 2 (20) = 40 liters of water
If we wanted the ratio of acid and water to be 3:1, then:
- 3x + x = 4x
Since we already have 40 liters of water and you can't remove stuff from the compound, we should use 40 as x. (3:1 means three parts of acid to one part of water, so the amount of water doesn't need to change)
- 3 (40) + 40 = 160
- 120 + 40 = 160
So the new compound has 120 liters of acid and 40 liters of water, and has the ratio 3:1. The amount of acid that should be added is:
- 120 - 60 = 60 liters of acid should be added.
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