Chemistry, asked by guptaanya06, 5 hours ago

A compound of C,H and O has , C =40.0% , H= 6.66% and O= 53.34% . What will be the empiricalformula of the compound?

Answers

Answered by Rajkd180203
0

Answer:

The Empreical formula will be

CH2O

Explanation:

Step 1 Divide percentage with Molar mass to find relative number of atoms

For Carbon

40/12 = 3.33

For Hydrogen

6.66/1 = 6.66

For Oxygen

53.34/16 = 3.33

Step 2

Find the simplest ratio for each element in the compound by taking the smallest relative number of atoms and divide the rest with it

For Carbon, 3.33/3.33 = 1

For Hydrogen = 6.66/3.33 = 2

For Oxygen = 3.33/3.33 = 1

The Emperical Formula will be CH2O.

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