A compound of C,H and O has , C =40.0% , H= 6.66% and O= 53.34% . What will be the empiricalformula of the compound?
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Answer:
The Empreical formula will be
CH2O
Explanation:
Step 1 Divide percentage with Molar mass to find relative number of atoms
For Carbon
40/12 = 3.33
For Hydrogen
6.66/1 = 6.66
For Oxygen
53.34/16 = 3.33
Step 2
Find the simplest ratio for each element in the compound by taking the smallest relative number of atoms and divide the rest with it
For Carbon, 3.33/3.33 = 1
For Hydrogen = 6.66/3.33 = 2
For Oxygen = 3.33/3.33 = 1
The Emperical Formula will be CH2O.
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