Question

A compound of formula a2b 3 has the hcp lattice which forms hcp lattice and what fraction of tetrahedral voids is occupied by the other atom

Answer 1

Answer:

The correct option is (4) hcp lattice - B, 1/3 Tetrahedral voids - A Explanation: Let B form hcp lattice no. of B = 6 tetrahedral void occupied by A = 1/3 x 12 = 4 A4B6 or A2B6

Answer 2

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• ❤.. The number of tetrahedral voids formed is equal to twice the number of atoms of element B and only 2/3rd of these are occupied by the atoms of element A.
• ❤..Hence the ratio of the number of atoms of A and B is ${2×(2/3):1 or 4:3}$ and the formula of the compound is ${A4B3}$.