a compound with molar mass 159 was found to contain 39.62% copper and 20.13% sulphur suggest molecular formula for the compound...????
Answers
Answer:
CuSO4
Explanation:
The percentage composition of the elements are :
Copper = 39.62%
Sulphur = 20.13%
The remaining amount is Oxygen hence the percentage mass of Oxygen is :
Oxygen = 100% - (20.13% + 39.62%) =
= 40.25%
Molar mass of copper = 63
Molar mass of Oxygen = 16
Molar mass of Sulphur = 32
Relative atomic mass of the elements is given by :
Copper = 39.62 g
Sulphur = 20.13 g
Oxygen = 40.25 g
The respective moles are :
Copper = 39.62/63 = 0.6288
Sulphur = 20.13/32 = 0.62906
Oxygen = 40.25/16 = 2.5156
We divide by the smallest mole to get the mole ratio.
Copper = 0.6288/0.6288 = 1
Sulphur = 0.62906/0.6288 = 1.0004
Oxygen = 2.5156/0.6288 = 4.0006
The Empirical formula of the compound :
CuSO4
From the Empirical formula we can get the molar mass.
63 × 1 + 32 × 1 + 16 × 4 = 159
Therefore this is the formula of the compound.
Answer:
CuSO4
Explanation:
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