Question

A compressed cylinder of gas contains 1.5 into ten power three g of N2 gas at pressure 2 into ten power seven Pascal and temperature of 17.1 degrees Celsius.what volume of gas has been released into atm of final pressure in cylinder is 1.8 into ten power five Pascal

Answer 1

Answer: Volume of the gas released will be  $1.66\times 10^{5} mL$.

Solution:

Given :

Volume of nitrogen gas :$V_1=1.5\times 10^{3}grams=1.5\times 10^{3} mL$  (1g = 1mL)

Pressure of nitrogen gas ;$P_1=2\times 10^{7}$pascal

Volume of nitrogen gas at pressure $P_2$ = $V_2$

Pressure of nitrogen gas at volume $V_2$ = $P_2=1.8\times 10^{5}$ pascals

According to Boyle's law:

$P_1V_2=P_2V_2$   (at constant temperature)

$(2\times 10^{7})(1.5\times 10^{3})=(1.8\times 10^{5})(V_2)$

On solving for $V_2$

$V_2=1.66\times 10^{5} mL$

Volume of the gas released will be  $1.66\times 10^{5} mL$