A computer cost 80000.its value depreciates every year at 4%,5%and 10%in 3years. Find its value after 3years.
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Answer:
value after first year
80000-(4%of 80000)
=80000-{4/100(80000)}
80000-3200=76800
value after 2nd year
76800-(5%of remaining 78000)
=76800-{5/100(76800)}
76800-3840=72960
value after 3rd year
72960-(10%of remaining 72960)
=72960-{10/100(72960)}
72960-7296=65664rs
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