A computer employs RAM chips of 256 x 8 and ROM chips of 1024 x 8. The computer
system needs 2K bytes of RAM, 4K bytes of ROM and 4 interface units, each with 4
registers. A memory mapped configuration is used. The two highest order bits of the
address bus are assigned 00 for RAM, 01 for of the ROM and 10 for interface registers.
Evaluate the following-
(i) How many RAM and ROM chips are needed?
(ii) Memory address map for the system.
(iii) The address range in hexadecimal for RAM, ROM and interface.
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Answer:
1. 2k bytes,RAM ,,4K BYTESROM
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