Physics, asked by neelamdeeo61, 1 year ago

a concave lens of focal length 15cm forms an image10cm from the lens.how far is the object placed from the lens ?Draw the ray diagram

Answers

Answered by nain31
12
 \bold{CONCAVE \: LENS}

A convex lens is thick at its periphery and thin in the middle.It diverges the rays of ligh that incident
upon it. It is also called diverging lens.


 \bold{GIVEN}

Focal length f= 15cm

Image distance v = 10 cm

By lens formula we know,

 \huge \boxed{ \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}}

 \mathsf{ \dfrac{1}{-15} = \dfrac{1}{-10} + \dfrac{1}{u}}

 \mathsf{ \dfrac{1}{u} = \dfrac{1}{15} + \dfrac{1}{-10}}

 \mathsf{ \dfrac{1}{u} = \dfrac{1}{15} - \dfrac{1}{10}}

 \mathsf{ \dfrac{1}{u} = \dfrac{2- 1}{30}}

 \mathsf{ \dfrac{1}{u} = \dfrac{1}{30}}

 \huge \boxed{\mathsf{ u = 30}}
Attachments:

Tivrta: you have put lens formula wrong
Tivrta: it is 1/f = 1/v - 1/u
Tivrta: and also .....
Tivrta: 1/15 -1/10 =
Tivrta: 2-3/30
Tivrta: which will be equal to
Tivrta: -1/30
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