A concave lens of focal length = 30cm if an object of size 4cm is placed 20cm from the lens find Nature, size and magnification of image.
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given, focal length of concave lens, f = -30cm
size of object = 4cm
object distance from the lens, u = -20cm
using lens maker formula,
1/v - 1/u = 1/f
or, 1/v - 1/-20 = 1/-30
or, 1/v = -1/20 - 1/30
or, 1/v = -5/60
or, v = -12 cm
magnification, m = v/u
size of image/size of object = (-12/-20)
or, size of image/4cm = 3/5
or, size of image = 2.4 cm
here it is clear that size of image is smaller than size of object.
Nature : virtual and diminished
Size : 2.4cm
magnification: 0.6
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