Question

A concave lens of length f forms an image which is 1/3 times the size of the object. Then, the angle distance of object from the lens is ​

Answer 1

Answer:

m=1/n= v/u = f/u+f

vu+vf=uf

uf=(u+f)×u/n => nf =(u+f)

u=(n-1)×f