Question

A concave mirror forms a real image four times as tall as the object placed 10 cm in front of mirror. Find the position of the image and the radius of curvature of the mirror. ​

Answer 1

Hope it helps you

Given : m = -4, u = -10 cm

m = -v/u

-4 = -v/-10  

v = -40 cm

Now, 1/f = 1/v + 1/u

1/f = 1/-10 + 1/-40 = (-4–1)/40 = -1/8

So, f = -8 cm and since R = 2f and so R = -16 cm

Answer 2

Answer:

Position of image=40 cm behind the mirror

Radius of curvature = -26.66cm

Explanation:

Concave mirror:

Height of object:h

Height of image:h'

h'=4h

Object distance (u)=-10 cm

By magnification formula,

h'/h= -v/u

4h/h=-v/(-10)

4=v/10

4×10=v

v=40cm

By mirror formula,

1/f=1/v+1/u

1/f=1/40+1/(-10)

1/f=1/40-1/10

1/f=(1-4)/40

1/f=-3/40

f= -40/3

f= -13.33cm

R=2f

R=2(-13.33)

R=-26.66cm

HOPE THIS BRING A SMILE IN YOUR FACE