a concave mirror forms an image of 2 cm high object on a screen placee 5cm away from mirror.the height of image is 50 cm find focal length and distance between mirror and object
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the image formed is of the same size and inverted,
therefore the magnification must be - 1 .
the magnification = image distance divided by object distance = v /u
if m=-1 then the object distance = -(image distance)
the relation ship between image distance (v) , object distance(u) and focal length is
1 /v + 1/u = 1/f
where f is the focal length of the mirror.
if v = u then 2 / u = 1/f
or u = 2.f = 40 cm
so the object must be placed at the centre of curvature as 2.f = R = radius of curvature.
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