A concave mirror has a focal length of 20 cm. Find the position or positions of an object for
which the image size is double of the object-size.
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Answer:
The focal length of the mirror is 20cm.
In the case of real image,
The object distance is u
1
, then the image distance will be −2u
1
.
The mirror formula is given as,
v
1
+
u
1
=
f
1
−2u
1
1
−
u
1
1
=
20
−1
u
1
=30cm
In the case of virtual image,
The object distance is −u
2
, then the image distance will be 2u
2
.
The mirror formula is given as,
v
1
+
u
1
=
f
1
2u
1
1
+
−u
1
1
=
20
−1
u
2
=10cm
The distance between two positions of object is given as,
u=30−10
=20cm
Thus the distance between the two positions of object is 20cm.
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