Question

a concave mirror has a radius of curvature of 0.3m . an object is placed at 25cm in front of mirror . find position ,nature and size of image​

Answer 1

Explanation:

f=30/2= - 15cm (focus of concave mirror)

u= -25

v=?

postion of image

1/v+1/u=1/f

1/v=1/f-1/u

1/-15+1/25

-5+3/75

-2/75

v= -37.5cm

which means that the image is behind the centre of curvature the concave mirror

nature of image

m= -v/u

-75/2*1/25 (- -=+)

-1.5so the image is times 1.5 bigger than the object and is inverted

thank you bro for telling me this mistake hope you like the answer