A concave mirror having the focal length 15cm,forms an image having twice the linear dimensions of the object.If the image is virtual,then the position of the object will be
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1/f=1/v - (-1/u)
1/15=1/2u + 1/u
1/15= 1+2/2u
1/15= 3/2u
2u = 15*3
u = 45/2 = 22.5 cm(position of object)
shalini110899:
But given answer -7.5cm
I'll let u know
i m sorry i did not see that its a concave lens
formula will be -1/f = -1/v -(-1/u)
u will get 7.5
thank u
welcome:g
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