Question

A concave mirror of focal length 10 cm. An object is placed at a distance of 15 cm from the mirror. Calculate the position of image, nature of image and size of image

Answer 1

Answer:

Hey there✌, Here is your answer ⏬ : ]

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Given:

u = -10 cm

v= ?

f = -15 cm

Applying mirror's formula:

$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$

Solution :

$\frac{1}{v}+\frac{1}{-10}=\frac{1}{-15}$

$\frac{1}{v}=\frac{-1}{15}+\frac{1}{10}$

$\frac{(-2+3)}{30}$

$\frac{1}{30}$

V = 30 cm.

Hence, we get enlarged image, virtual in nature having magnification 3.

Thanks : ]

Answer 2

Explanation:

Focal length-10cm

object distance- -15cm

image distance-?

using of lens

1/F=1/u-1/v

1/v= 1/15-1/10

1/V=1/-30

magnification-h¹/h

-15×-30/-15

- 30

the image is inverted and real.thus the image formed is real, inverted and enlarged.