Math, asked by ayushdash97709, 4 months ago

a concave mirror of focal length 10cm dipped in water if it's refractive index is 4/3 and s is in the principal axis find the final image formed

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Answered by trishasingh464350
0

Answer:

12th

Physics

Ray Optics and Optical Instruments

Combination of Lenses

The convex surface of a thi...

PHYSICS

The convex surface of a thin concavo-convex lens of glass of refractive index 1.5 has a radius of curvature 20 cm. The concave surface has a radius of curvature 60 cm. The convex side is silvered and placed on a horizontal surface.

If the concave part is filled with water of refractive index 4/3, find the distance through which the pin should be moved so that the image of the pin again coincides with the pin?

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ANSWER

For refraction from the first surface,

v

1

3

4

−x

1

=

3

4

For refraction through the second surface,

v

2

2

3

v

1

3

4

=

−60

2

3

3

4

For the final image to form on the object itself, the image from this refraction should be at the center of curvature of the concave mirror.

Thus, v

2

=−20cm

Solving the above equations gives-

x=13.85cm

Thus the pin should be moved 1.15 cm down.

Answered by lovedeepgehal
1

Answer:

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