A concave mirror of focal length 10cm is placed at a distance of 35 cm
from a wall. How far from the wall an object be placed so that the image
formed by the mirror falls on the wall?
Answers
Answered by
180
f=-10 cm
u=-35 cm
1/v=1/f- 1/u
1/v=-1/10+1/35
1/v=-7+2/70
1/v=-5/70
v=-14 cm
wall should be placed at distance of 14 cm from the mirror
u=-35 cm
1/v=1/f- 1/u
1/v=-1/10+1/35
1/v=-7+2/70
1/v=-5/70
v=-14 cm
wall should be placed at distance of 14 cm from the mirror
Answered by
210
Hello friend
___________________________________
Focal length of the mirror is 10cm
Distance from the wall is 35cm
It needs to form an image on the wall
That is the image distance will be 35cm
We need to find the object distance
By using mirror formulae
1/f = 1/v + 1/u
Using sign convention
1/-10 = 1/-35 + 1/u
-1/10 + 1/35 = 1/u
(-7+2)/70 = 1/u
-5/70 = 1/u
-1/14 = 1/u
u=-14
The object should be placed at a distance of 14cm infront of the mirror.
It means it should be placed at a distance of 35-14=21cm from the wall
___________________________________
Hope it helps!
___________________________________
Focal length of the mirror is 10cm
Distance from the wall is 35cm
It needs to form an image on the wall
That is the image distance will be 35cm
We need to find the object distance
By using mirror formulae
1/f = 1/v + 1/u
Using sign convention
1/-10 = 1/-35 + 1/u
-1/10 + 1/35 = 1/u
(-7+2)/70 = 1/u
-5/70 = 1/u
-1/14 = 1/u
u=-14
The object should be placed at a distance of 14cm infront of the mirror.
It means it should be placed at a distance of 35-14=21cm from the wall
___________________________________
Hope it helps!
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