Physics, asked by priyranjan95, 1 month ago

A concave mirror of focal length 12 cm is placed at a distance of 60 cm from a wall. How far from the wall an

object be placed so that its sharp image formed by the mirror falls on the wall?​

Answers

Answered by abhi178
0

The distance of object from the wall be 45 cm.

A concave mirror of focal length 12 cm is placed at a distance of 60 cm from a wall.

We have to find the distance from the wall of an object to be placed so that its sharp image formed by the mirror falls on the wall.

See the diagram,

Let the distance of the object from the wall be x.

∴ object distance from the mirror, u = -(60 - x) cm

Here, focal length, f = -12cm

image distance from the mirror, v = - 60cm

Using formula, 1/v + 1/u = 1/f

⇒ 1/-60 + 1/-(60 - x) = 1/-12

⇒ 1/(60 - x) = 1/12 - 1/60 = (5 - 1)/60

⇒ 1/(60 - x) = 1/15  

⇒ x = 45 cm

Therefore the distance of object from the wall be 45 cm.

Attachments:
Answered by sourasghotekar123
0

Step 1: Given data

focal length, f=12cm

distance of mirror from the wall =60cm

object distance, u=?

Step 2: Calculating the object distance

Let,

distance of the object from the wall =x

\therefore object distance from the mirror, u = -(60 - x) cm

Since, it is a concave mirror,

f=-12cm

Since, the image formed is sharp,

image distance, v=-60cm

Using the mirror formula,

\frac{1}{f} =\frac{1}{v}+\frac{1}{u}

\frac{1}{-12}=\frac{1}{-60}+\frac{1}{-(60-x)}

\frac{1}{60-x} =\frac{1}{12} -\frac{1}{60}

\frac{1}{60-x} = \frac{5-1}{60}

\frac{1}{60-x}  = \frac{1}{15}

60-x=15

x=60-15=45cm

Hence, the distance of the object from the wall is 45cm.

#SPJ2

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