a concave mirror of focal length 20cm forms and virtual image whose size is 2.5 times the size of object find the object distance
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Answered by
0
Answer:
u=(-1.2)cm
Explanation:
f=-20cm
m=+2.5
m= (-v)/u
u= (-v)/m -----(1)
1/f=1/v+1/u
1/(-20) = 1/v + 2.5/(-v) {substituting
= (1-2.5)/v
==> v= (-1.5)*(-20)
= +30
from (1)
u= -v/m
= -30/2.5
=-6/5
= (-1.2)
Answered by
0
Answer:
I'll tell u later
no need to tension
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