Question

a concave mirror of focal length f can form a magnified erect as well as an inverted image of an object placed in front of it.justify this statement stating the position of the object with respect to the mirror.

Answer 1

Let the focal length of the mirror be 10 cm

Let's take any position of the object like 15 cm = u

According to mirror formula

1/f = 1/u + 1/v

1/v = 1/f - 1/u

1/v = -1/10 - ( -1/15)

1/v = -1/10+1/15

1/v = -3+2/30

1/v = -1/30

v = -30 cm

m = -v/u

m = -(-30)/-15

m = -2

Therefore the image is magnified inverted and real

Now if u = 5 cm then,

1/v = -1/10+1/5

1/v = -1+2/10

1/v = 1/10

v = 10 cm

Therefore the image is virtual.

m = -v/u

m = -10/-5

m = 2

Therefore the image is virtual erect and magnified

Hence Both the cases are true for concave mirror.

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Answer 2

Magnified erect image will be formed when the object is between F and Pole of the mirror.

Inverted image will be formed when the object is beyond the focal length of the mirror away from the pole.

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