A concave mirror of radius of curvature 20cm
produced an inverted image 3 times the size of
an object placed of the mirror and perpendicular to the axis. Calculate the position of the object and image.
Answers
Answered by
6
Hope it may help you.
Attachments:
Answered by
8
Answer:
u=13.3cm
v=39.99cm
Explanation:
f=r/2
20/2= 10cm
h1=h0
h1=3h
using magnification formula(m) =h1/h0=v/u
3h0/ho=v/u
v=3u
1/f=1/v+1/u
1/10=1/3u+1/u
1/10=4/3u
40=3u
u=13.3cm
v=3u
v=3(13.3)
v=39.99cm
Similar questions